$sql = "select state from servicer where servicer_id=? and password=?";执行上面这句返回的结果为1
$sql = "call login(?,?)";执行这句却出错
Warning: mysqli_stmt::bind_result(): Number of bind variables doesn't match number of fields in prepared statement
select state from servicer where servicer_id=user_id and password=pw;存储过程是上面这句，附带两个参数
IN `user_id` char(20),IN `pw` char(20)
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